Binomial distribution

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The manufacturer of a fertilizer guarantees that, with the aid of the fertilizer,65% of planted seeds will germinate. Suppose the manufacturer is correct. If 9 seeds planted with the fertilizer are randomly selected, what is the probability that fewer than 7  of them germinate? Carry your intermediate computations to at least four decimal places, and round your answer to at least two decimal places. We have a binomial distribution with n = 9 and p = 0.65 P(X = s) => 9Cs(0.65)^s(0.35)^(9 – s) More than 7 successes => either 8 or 9 successes P(X = 8) => 9C8(0.65)^8(0.35)¹ P(X = 9)…

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