Consider the constants A, B, C and the functionf(x, y) = Ax^2 + Bxy + Cy^2.Show that the only choice of coefficients A, B, C giving ?^2f/?x^2+?^2f/?y^2= 2, are A=1-s2 B=s1 C=s2where s1, s2 are arbitrary.f(x, y) = Ax^2 + Bxy + Cy^2. ?f/?x = 2Ax + By?f/?y= Bx + 2Cy ?^2f/?x^2 = 2A?^2f/?y^2 = 2C ?^2f/?x^2+?^2f/?y^2 = 2A + 2C = 2Therefore A + C = 1Taking B = s1 and C = s2 (…
Consider the constants A, B, C
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